SOLUTION: Two marbles are drawn one after the other without replacement from a bag that contains:
9 red marbles, 8 blue marbles, and 3 green marbles.
Find the probability of the following
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Question 1155507: Two marbles are drawn one after the other without replacement from a bag that contains:
9 red marbles, 8 blue marbles, and 3 green marbles.
Find the probability of the following events.
(a) One red marble and one green marble are drawn in either order.
The probability is :
(b) Two blue marbles are drawn.
The probability is :
(c) At least one marble is drawn that is not blue.
The probability is :
(d) The second marble is green if we know that the first marble is green.
The probability is:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2 ways to do this with equal probability 9/20*3/19 RG
3/20*9/19 GR
That is 54/380 or 27/190 =0.142
BB is 8/20*7/19=56/380 or 14./95=0.147
Find probability both are blue which is 0.147. So at least 1 that is not blue is everything else or 0.853
if first marble is green, there are 19 left, 2 of which are green, so the probability is 2/19=0.105
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