SOLUTION: A box contains 7 yellow, 15 green and 17 red jelly beans. If 2 jelly beans are selected without replacement, what is the probability that: a) Exactly 1 is yellow and 1 is gree

Algebra.Com
Question 1155501: A box contains 7 yellow, 15 green and 17 red jelly beans.
If 2 jelly beans are selected without replacement, what is the probability that:
a) Exactly 1 is yellow and 1 is green?
Answer by ikleyn(52777)   (Show Source): You can put this solution on YOUR website!
.

There are  7 + 15 + 17 = 39 jelly beans, in all.


    P(1st is yellow, 2-nd is green) =  = 


    P(1st is green, 2-nd is yellow) =  = 


    P(final) = the sum =  = 0.1417.    ANSWER

Solved.



RELATED QUESTIONS

A box contains 17 yellow, 29 green and 36 red jelly beans. If 12 jelly beans are... (answered by robertb)
A box contains 15 yellow, 29 green and 36 red jelly beans. If 10 jelly beans are... (answered by Edwin McCravy)
A box contains 21 yellow, 24 green and 27 red jelly beans. If 13 jelly beans are... (answered by stanbon)
A box contains two red, five green, six black, and four blue jelly beans. In how many... (answered by edjones)
A box contains 21 yellow, 28 green and 38 red jelly beans. If 14 jelly beans are selected (answered by jim_thompson5910)
please help me with this question:A box contains 25 yellow, 26 green and 36 red jelly... (answered by stanbon)
A box contains 23 yellow, 30 green and 31 red jelly beans. If 14 jelly beans are... (answered by Edwin McCravy)
Two jelly beans are selected, one at a time from a bowl containing 10 black, 10 red and... (answered by stanbon)
A jar contains 15 red jelly beans, 12 yellow jelly beans, and 18 orange jelly beans.... (answered by EdenWolf)