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In a jar there are five balls of different colors (blue, green, red, purple and white). You pull out three of them without putting anyone back.
(a) How many of the samples contain blue and / or green?
(b) How many of the samples contain both blue and green?
(c) How many of the samples contain neither blue nor green?
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First, notice that among 5 balls, there are exactly 1 ball of each of the 5 colors.
Next, according to the context, the order of balls in each selected triple does not matter.
(a) Question (a) is not precisely clear to me, therefore, I will not answer it.
(b) Blue and green just are present in each selected sample, and they can be completed by either of the 3 remaining balls.
So the answer in this case is 3.
(c) The samples that contain neither blue nor green are comprised of other (remaining) colors.
There is only one possible triple of such kind.
The answer is 1.
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Comment from student: Hi ikleyn, Thank you for your urgent response to my question.
However, I am a bit confused with your answer. The reason is because, I looked at this task in the context of probability.
If so, can we have a probability greater than 1?
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My response.
Hello, I got this comment from a visitor. But since it came with no reference to the problem,
I don't know to WHICH PROBLEM it relates.
If it relates to THIS problem, then where do you see the word "probability" in your post?
In the future, if you want to have a DIALOG, then PLEASE REFER to the ID number of the problem, which is 1154216 in this case.
If the comment and the question do not relate to this problem, then ignore/disregard my post.
Have a nice day (!)