.
Of 36 elements of the sample space, there are 6 doubles
(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)
and 3 separate outcomes (4,6), (5,5) and (6,4) for a total of 10.
Of these 3 separate outcomes, one pair (5,5) is just accounted as a double.
Therefore, the probability under the problem'a question is
P = = = . ANSWER
Solved.
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If you want to learn this subject and this class of problems BETTER, DEEPER and WIDER, look into the lesson
- Rolling a pair of fair dice
in this site. You will find there many other similar solved problems.
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- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Solved problems on Probability".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.