SOLUTION: A die is tossed twice. Find the probability of getting a 3 or 4 on the first toss and a 1 or a 2 on the second toss.

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Question 1153820: A die is tossed twice. Find the probability of getting a 3 or 4 on the first
toss and a 1 or a 2 on the second toss.

Answer by ikleyn(52821)   (Show Source): You can put this solution on YOUR website!
.

Recall that the outcome of rolling a die is any of 6 integer numbers from 1 to 6 inclusive, 

with the uniform probability of  for each outcome.


Therefore,  P(getting 3 or 4 on the first toss) =  = 

and         P(getting 1 or 2 on the second toss) = ,  again.


The events/outcomes are INDEPENDENT on the first and the second tosses;

therefore, the final probability under the question is the    = .    ANSWER

Solved.

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If you want to learn this subject and this class of problems  BETTER,  DEEPER  and  WIDER,  look into the lesson
    - Rolling a pair of fair dice
in this site.  You will find there many other similar solved problems.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Solved problems on Probability".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


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