SOLUTION: A box contains 5 green marbles, 7 blue marbles, and 9 red marbles. Three marbles are selected at random from the box, one at a time, without replacement. Find the probability

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Question 1153539: A box contains 5 green marbles, 7 blue marbles, and 9 red marbles.
Three marbles are selected at random from the box, one at a time, without replacement.
Find the probability that the first two marbles selected are not red, and the last marble is red.
Answer by ikleyn(52777)   (Show Source): You can put this solution on YOUR website!
.

In all, there are 5+7+9 = 21 marbles.


Of them, 5 are red and 21-5 = 16 are not red.


Therefore, the probability under the question is


    P =  = 0.150376.      ANSWER

Solved.


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