SOLUTION: A bag contains 15 black balls, 8 green balls and 10 white balls. If the three balls are drawn a: with replacement b: without replacement Find if the balls are: i. of the same

Question 1152270: A bag contains 15 black balls, 8 green balls and 10 white balls. If the three balls are drawn
a: with replacement
b: without replacement
Find if the balls are:
i. of the same colour
ii. of different colour
iii.two are black one green
iv.two are white one is black
v. two are green one is black
vi. non are black
vii. non are green
viii. non are green
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
With replacement and 33 balls total
1. Same color (15/33)^3+(8/33)^3+(10/33)^3
2. different color 1- answer above.
3. two black and one green- 3 ways to happen so 3*(15/33)(15/33)*8/33
4. two white and one black- 3(10/33)(10/33)(15/33)
5. this would be 3*(8/33)(8/33)(15/33)
6. none is black (18/33)(18/33)*18/33)
7. none is green (25/33)^3
with replacement
1. (15/33)(14/32)(13/31)+(8/33)*(7/32)(6/31)+(10/33)(9/32)(8/31)--here, the numerator decreases by 1 and the denominator as well after each draw.
2.1- the above answer for different color.
3. 2 black 1 green. the factors change, but their product does not.
this is 3(15/33)(14/32)(8/31)
4. 2 white and one black is 3(10/33)(9/32)(15/31)
5. 2 green and one black is 3(8/33)(7/32)(15/31)
6. none is black (18/33)(17/32)(16/31)
7. none is green (25/33)(24/32)(23/31)
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