SOLUTION: An urn contains 4 balls numbered 0 through 3. One ball is selected at random and removed from the urn and not replaced. All balls with nonzero numbers less than that of the selec

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Question 1151293: An urn contains 4 balls numbered 0 through 3. One ball is selected at
random and removed from the urn and not replaced. All balls with nonzero
numbers less than that of the selected ball are also removed from the urn.
Then a second ball is selected at random from those remaining in the urn.
What is the probability that the second ball selected is numbered 3?

Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!

The first selection from {0,1,2,3} is 1/4 for each ball. Now we need to look at what happens for each of these selections:
First Sample space
selection for 2nd selection Pr{2nd pick is 3}
---------- ----------------- -----------------
0 {1,2,3} (1/4)(1/3)
1 {0,2,3} (1/4)(1/3)
2 {0,3} (1/4)(1/2)
3 {0} (1/4)(0)
Adding up all the probabilities for a 3 on 2nd pick:
or about 29.2%
Check:
The other numbers probabilities: Pr{0} = 11/24, Pr{1} = 2/24, Pr{2} = 4/24
Adding these should give 1: (11+2+4+7)/24 = 24/24 = 1 (ok)

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