SOLUTION: If X is normally distributed on (5,4) then what is the probability that 8 < Y < 13 where Y = 2X + 1?

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Question 1150738: If X is normally distributed on (5,4) then what is the probability that
8 < Y < 13 where Y = 2X + 1?

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
The mean is 2(mean of x)+1 or 11
the variance is the square of the coefficient or 4 times the variance of the original.
The sd of the original was 4, so its variance was 16 and the new variance is 64 with a sd of 8
y is distributed normally with mean of 11 and sd of 8.
z=(x-mean)/sd
so z for the low end is (8-11)/8 or -3/8
and for the high end is (13-11)/8 or +1/4
for z to be between these two values gives a probability of 0.2449

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