SOLUTION: Two numbers are randomly selected (with replacements) from the first 12 positive integers. What is the probability that the sum of these two numbers is 10?

Question 1150462: Two numbers are randomly selected (with replacements) from the first 12 positive integers. What is the probability that the sum of these two numbers is 10?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Answer deleted; I overlooked the "with replacements" in the statement of the problem.

Answer by ikleyn(52779) (Show Source): You can put this solution on YOUR website!
.

The number of all possible outcomes is 12*12 = 144. It is the number of all pairs (a,b) with integers "a" and "b" from 1 to 12 inclusive. The favorable pairs are (1,9), (2,8), (3,7), (4,6), (5,5), (6,4), (7,3), (8,2) and (9,1). The number of favorable pairs is 9. The probability under the question is P = = . ANSWER

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