SOLUTION: A problem in Mrs. Schrader's geometry class has four steps in the proof. She writes the steps, one per card, and gives them to a student to put in proper sequence. How many differe

Question 1149500: A problem in Mrs. Schrader's geometry class has four steps in the proof. She writes the steps, one per card, and gives them to a student to put in proper sequence. How many different sequences of steps are possible?

Answer by ikleyn(52921) (Show Source): You can put this solution on YOUR website!
.


4 items (cards) can be re-arranged in 4! = 4*3*2*1 = 24 ways.    ANSWER

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It is about PERMUTATIONS.

On Permutations, see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations

    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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