SOLUTION: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal p
Algebra.Com
Question 1149472: Find the mean and standard deviation for a binomial distribution with 912 trials and a probability of success of 0.21 and enter the answers below. Round each value to two decimal places.
Mean:
Standard deviation:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean is np=912*0.21=191.52
variance is np(1-p)=912.52*0.79=151.3008
sd is sqrt (V)=12.30
RELATED QUESTIONS
Find the mean and standard deviation for 20 trials for a binomial probability... (answered by stanbon)
Assume that a procedure yields a binomial distribution with n trials and the probability... (answered by stanbon)
Consider the binomial distribution of 36 trials with a P (success)=p=0.64
1.... (answered by oscargut)
The standard deviation of a Binomial distribution with 48 observations and probability of (answered by Solver92311)
Assume that a procedure yields a binomial distribution with n=330 trials and the... (answered by Theo)
Assume that a procedure yields a binomial distribution with n trials and the probability... (answered by ewatrrr)
The mean of a Binomial distribution with 10 observations and probability of success 0.5,... (answered by Solver92311)
Consider a binomial random variable where the number of trials is 9 and the probability... (answered by jim_thompson5910)
A binomial distribution is based on n = 15 trials and success probability p = 0 4. . What (answered by mathmate)