.
The number of ways to choose a cone, if order doesn't matter, is equal to the number of combinations
of 14 different items taken 3 at a time
= = 364. ANSWER
So, you may have new combination of flavors practically every day in a year . . .
Solved.
---------------
On Combinations, see introductory lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
/\/\/\/\/\/\/\/\/
Dear robbyjenns (!)
Your problem has the question
In how many ways can you choose a cone if the order of the flavors doesn't matter?
It is just enough for us, the tutors, and we fully understand your post.
But then it has one more line
The number of ways to choose a cone, if order doesn't matter, is
Dear robbyjenns,
may I ask you DO NOT INCLUDE this line and such lines in other yours future posts, in order for we, the tutors, feel our-self comfortably ?
Otherwise I (me) and some other tutors feel our-self as a kind of idiots . . .
Thank you very much for your understanding . . .