SOLUTION: Determine if the outcome is unusual. Consider as unusual any result that differs from the mean by more than 2 standard deviations. That is, unusual values are either less than μ

Question 1146267: Determine if the outcome is unusual. Consider as unusual any result that differs from the mean by more than 2 standard deviations. That is, unusual values are either less than μ - 2σ or greater than μ + 2σ.
The Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than .4 ounces. Suppose that 800 jawbreakers are selected at random from the production lines. Would it be unusual for this sample of 800 to contain 517 jawbreakers that weigh more than .4 ounces?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
normal approximation may be used
mean is np=0.6*800=480
variance is np(1-p)=400*.4=160
sd is sqrt (160)=12.65
z=(x-mean)/sd
=(517.5-480)/12.65
=37.5/12.65
=2.90
probability of z>2.90 is 0.002
It would be unusual.

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