SOLUTION: According to a report, 9.5% of all full-time S.A. undergraduate students study abroad. Assume that 60% of the undergraduate students who study abroad are female and that 49% of the

Question 1145848: According to a report, 9.5% of all full-time S.A. undergraduate students study abroad. Assume that 60% of the undergraduate students who study abroad are female and that 49% of the undergraduate students who do not study abroad are female. A full-time S.A. undergraduate student is randomly selected.
2.1) What is the probability that the student is female and studying abroad (rounded off to three decimals)? [2]
2.2) What is the probability that the student is female and not studying abroad (rounded off to three decimals)? [2]
2.3) What is the probability that the student is female (rounded off to four decimals)? [3]
2.4) What is the probability that the student is male (rounded off to four decimals)? [1]
2.5) What is the overall percentage of full-time female students and male students (rounded off to zero decimals)?

Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website!
% of full-time S.A. undergraduate students who study abroad = 0.095
% of full-time S.A. undergraduate students who do not study abroad = 0.905

% of undergraduate students who study abroad that are female = 0.60
% of undergraduate students who study abroad that are male = 0.40

% of undergraduate students who not do study abroad that are female = 0.49
% of undergraduate students who not do study abroad that are male = 0.51

2.1) What is the probability that the student is female and studying abroad (rounded off to three decimals)?

0.60 * 0.095 = 0.057

2.2) What is the probability that the student is female and not studying abroad (rounded off to three decimals)?

0.49 * 0.905 = 0.443

2.3) What is the probability that the student is female (rounded off to four decimals)?

(0.60 * 0.095) + (0.49 * 0.905) = 0.057 + 0.443 = 0.500

2.4) What is the probability that the student is male (rounded off to four decimals)?

(0.40 * 0.095) + (0.51 * 0.905) = 0.038 + 0.462 = 0.500

Or...you could have simply subtracted the result from Question 2.3 from 1.

2.5) What is the overall percentage of full-time female students and male students (rounded off to zero decimals)

From last two questions...50/50.
RELATED QUESTIONS
Blue Nile University recently conducted a survey of undergraduate students in order to... (answered by ikleyn)

Table 8 lists enrollment in U.S. degree-granting institutions for both undergraduate and... (answered by josmiceli)

Hi! can please help me with this question ? Thankyou! The dean of Faculty of... (answered by CPhill,ikleyn)

Blue Nile University recently conducted a survey of undergraduate students in order to... (answered by Boreal)

An accounting professor claims that no more than one-quarter of undergraduate business... (answered by stanbon)

An accounting professor claims that one quarter of undergraduate business students major... (answered by stanbon,Edwin McCravy)

The U.S. Department of Education reports that 46% of full-time college students are... (answered by Boreal)

An article in the San Jose Mercury News stated that students in the California state... (answered by Boreal)

1. 49% of undergraduate students at unversity are women. If there are 4116 female... (answered by macston)