SOLUTION: Suppose a number is chosen at random from the set {0,1,2,3,...,1739}. What is the probability that the number is a perfect cube?
Round your answer to 6 decimal places as needed.
Algebra.Com
Question 1145676: Suppose a number is chosen at random from the set {0,1,2,3,...,1739}. What is the probability that the number is a perfect cube?
Round your answer to 6 decimal places as needed.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If you take the cube root of 1739, you get 12 plus a fraction. That means that 12 cubed (1728) is the largest perfect cube in the given set. So there are exactly 13 perfect cubes counting zero cubed in the set. The probability of anything is the number of successful outcomes divided by the total number of outcomes. You can do your own arithmetic from here.
John
My calculator said it, I believe it, that settles it
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