(A) The probability that all 3 children are of the same gender = = The probability of= to have 3 girls PLUS the probability of = to have 3 boys = = + = = . ANSWER (B) P = P(BBG) + P(BGB) + P(GBB) + P(GGB) + P(GBG) + P(GGB) = = . ANSWER Notice that the probability of the n.B is the complement to the probability of the n.A, as it should be. It is an additional argument/check that the solution is correct.