SOLUTION: In a random selected family of three biologically theirs, normally conceived children, find the probability that this family has: A.) all children of the same gender B.) Only tw

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Question 1144390: In a random selected family of three biologically theirs, normally conceived children, find the probability that this family has:
A.) all children of the same gender
B.) Only two children of the same gender

Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.

            Assuming that the probability to have in a family a boy  (B)  or a girl  (G)  is   


(A)  The probability that all 3 children are of the same gender =     


         = The probability of   =   to have 3 girls 

     PLUS

           the probability of   =   to have 3 boys =


     =  +  =  = .    ANSWER




(B)  P = P(BBG) + P(BGB) + P(GBB) + P(GGB) + P(GBG) + P(GGB) =  = .     ANSWER



Notice that the probability of the n.B  is the complement to the probability of the n.A, as it should be.


It is an additional argument/check that the solution is correct.

Solved.


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