SOLUTION: A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing. a. How many different combinations of 3 cans could be selected? b. What i

Question 1142661: A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.
a. How many different combinations of 3 cans could be selected?
b. What is the probability that the contaminated can is selected for testing?
Answer by ikleyn(53937) (Show Source): You can put this solution on YOUR website!
.

(a)   =  = 2024 different combinations of 3 cans.



(b)    =  =  = 253 different combinations of 3 cans, containing the contaminated one.


      (You can form all possible combinations by adding any two other cans to the contaminated one).


      The probability is   = 0.125.

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