SOLUTION: the average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. Suppose 100 golfers played the course today. Fund the probability that the
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Question 1141814: the average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. Suppose 100 golfers played the course today. Fund the probability that the average score of 100 golfers exceeded 77.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z=(x bar-mean)/sigma/sqrt(n)
>=(77-76)/5/sqrt(100)
>=1*10/5
>=2
That probability is 0.0228
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