SOLUTION: You choose a tile at random from a bag containing 2A's, 3B's, and 4C's. You replace the first tile in the bag and then choose again. Find each probability. P(A and A) P(A and B

Algebra.Com
Question 1141253: You choose a tile at random from a bag containing 2A's, 3B's, and 4C's. You replace the first tile in the bag and then choose again. Find each probability.
P(A and A)
P(A and B)
P(B and C)

Answer by rothauserc(4718)   (Show Source): You can put this solution on YOUR website!
There are 9 tiles in the bag
:
P(A and A) = (2/9) * (2/9) = 4/81
:
P(A and B) = (2/9) * (3/9) = 6/81 = 2/27
:
P(B and C) = (3/9) * (4/9) = 12/81 = 4/27
:

RELATED QUESTIONS

You choose a tile at random from a bag containing 2 A's, 3 B's, and 4 C's. You replace... (answered by ikleyn)
You choose a tile at random from a bag containing 3 A's, 2 B's, and 4 C's. You replace... (answered by ikleyn)
In a word game, you choose a tile from a bag, replace it, and then choose another. If... (answered by richwmiller,edjones)
A bag has 6 number tiles numbered one through six. You draw a number tile, replace the... (answered by checkley77)
A bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. What is the... (answered by stanbon)
a bag contains 4 red tiles, 3 blue tiles, 2 green tiles, and 1 yellow tile. A tile is... (answered by jim_thompson5910)
A bag contains green and yellow color tiles. You pick two tiles at random with out... (answered by edjones)
A bag contains green and yellow color tiles. You pick two tiles at random with out... (answered by stanbon)
18. Thomas, Jenna, and Maria are playing a game. They have a bag that contains 39 white... (answered by rfer)