SOLUTION: A five digit number is formed using digits 0 1 2 3 and 4 without repetition. Find the chance that the number is divisible by 5.

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Question 1141202: A five digit number is formed using digits 0 1 2 3 and 4 without repetition. Find the chance that the number is divisible by 5.
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A five digit number is formed using digits 0 1 2 3 and 4 without repetition. Find the chance that the number is divisible by 5.
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The units digit has to be 5 or zero to be divisible by 5. There's no 5, so it has to be zero.
---> 1 out of 5
============
Not sure about "the chance."
Probability is 1/5
Odds are 1:4

Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
First, let us calculate the number of all possible five digit numbers formed using the digits 0, 1, 2, 3 and 4 without repetition.


The leftmost digit can be any of four digits 1, 2, 3 or 4, which gives 4 options.


The next digit can be any of 4 remaining digits, which gives 4 options.


Using similar arguments, you will get 4*4*3*2*1 = 96 for the number of all possible five digit numbers formed 
using the digits 0, 1, 2, 3 and 4 without repetition.


The numbers divisible by 10 are those of them that ended by 0 (by zero),
and the number of such numbers is 4*3*2*1 = 24.


Thus the probability  P  under the question is the ratio  


    P =  =  = 0.25 = 25%.      ANSWER


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