SOLUTION: If 3.5% of 80,000 parts are defective (2800) then what is the probability of pulling 20,000 random parts with zero defects? What is the formula to answer the question and the pro

Question 1139182: If 3.5% of 80,000 parts are defective (2800) then what is the probability of pulling 20,000 random parts with zero defects?
What is the formula to answer the question and the probability please.
Answer by ikleyn(53751) (Show Source): You can put this solution on YOUR website!
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From the first statement, the probability for any one part to be defective is  P = 0.035   (which is 3.5%).


It means that the probability for any one part to be fair (with no defects) is  Q = 1 - 0.035 = 0.965.


Then the probability for 20,000 parts to be with zero defects is   =  = .


It is the formula you are asking for.    ANSWER

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