SOLUTION: An urn has 6 balls that are identical except that 3 are white and 3 are red. A sample of 4 is selected randomly without replacement.
What is the probability that exactly 2 are whi
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Question 1139066: An urn has 6 balls that are identical except that 3 are white and 3 are red. A sample of 4 is selected randomly without replacement.
What is the probability that exactly 2 are white and 2 are red?
What is the probability that at least 2 of the balls are white?
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Probability(P) 2 are white and 2 are red = 3/6 * 2/5 * 3/4 * 2/3 = 36/360 = 1/10
:
at least two balls are white means we can have 2 white and 2 red or 3 white and 1 red, we already have the probability for 2 white and 2 red, that is, 1/10
:
P 3 are white and 1 is red = 3/6 * 2/5 * 1/4 * 3/3 = 18/360 = 1/20
:
P at least 2 are white = 1/10 + 1/20 = 3/20
:
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