SOLUTION: On the midnight shift, the number of patients with head trauma in an emergency room has the probability distribution shown below. x 0 1 2 3 4 5

Question 1138410: On the midnight shift, the number of patients with head trauma in an emergency room has the probability distribution shown below.

x 0 1 2 3 4 5 Total
P(x) .05 .44 .30 .17 .03 .01 1.00

(a) Calculate the mean and standard deviation. (Round your mean value to 2 decimal places and standard deviation to 3 decimal places.)
I know that the total is 1.0 to find the mean I divided by number of sets which would be 5. I assumed it would be .20. The homework help I have is saying it is incorrect. I am very unsure and thought I was headed in the right direction. The single digits are above each set of numbers but even though it looks right how I typed it for you to read...it doesn't come out that way on the preview. So for example 0 has the .05 under it. If you slide all the single digits representing each set of numbers above the decimal numbers. Hope that part makes sense. Total should be above the 1.00. It isn't showing up correctly on the preview for some reason.
Please help and thanks.
Tonya
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
There are six groups
0--.05--0 product
1--.44--,.44
2--.30--.60
3--.17--.51
4--.03--.12
5--.01--.05
Sum is 1.72

.05--.44-.30-.17--.03--.01
0. 1. 2. 3. 4. 5
0. .44. ,60. .51. .12. .05=1.72 mean or expected value
.148+.228+.024+.279+.156+.108=0.943 sum of squared deviations * probability
sd is sqrt (0.943)=0.971
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