SOLUTION: I have now have 12 M&Ms, all of varying colors. Suppose I want to select 3 M&Ms from these 12 to decorate a homemade necklace. How many different color orderings are there if I am

Question 1136925: I have now have 12 M&Ms, all of varying colors. Suppose I want to select 3 M&Ms from these 12 to decorate a homemade necklace. How many different color orderings are there if I am selecting 3 M&Ms and the order of the M&Ms that I am selecting matter?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Since order matters, you have 12 choices for the first, then 11 choices for the second, then 10 choices for the third. The total number of ordered selections of 3 of the 12 M&Ms is 12*11*10 = 1320.
RELATED QUESTIONS
I have a bag of m&ms how to i figure out the probability of choosing 2 different colors. (answered by stanbon)

According to Masterfoods, the company that manufactures M&Ms, 12% of peanut M&Ms are... (answered by Boreal)

A bag of M&Ms has 50 M&M pieces. Of these, 20 M&M pieces are brown, 16 pieces are red, 8... (answered by ewatrrr)

According to the company that makes M&Ms, each package of Milk Chocolate M&M�s should... (answered by JulietG)

Reference question 1042438: I have found the problem with answers: A: s / 3 + 4m... (answered by josgarithmetic,MathTherapy)

I just want to make sure that i have done this correctly. Simplify... (answered by stanbon,praseenakos@yahoo.com)

David hikes 2 1/2 miles in a half hour. What is his rate in miles per hour? How long... (answered by MathLover1)

Suppose we want to choose 7 colors, without replacement, from distinct 12 colors. (answered by ikleyn)

Mars Inc, claims 24% of M&M plain candies are blue. Suppose that a sample of 100 M&Ms are (answered by edjones)