Let X and Y represent discrete random variables with probability density function for x ∈ {1,2,3} and y ∈ {1,2}.
Compute P(X = 1 and Y = 2) and P(X +Y = 4).
(a) P(X = 1 and Y = 2) = f(1,2) == = . ANSWER (b) Notice that X + Y = 4 is possible only if (X=3 AND Y=1) OR (X=2 AND Y=2). Therefore, P(X + Y = 4) = P(X=3 AND Y=1) + P(X=2 AND Y=2) = f(3,1) + f(2,2) = + = = . ANSWER