SOLUTION: An elevator has a placard stating that the maximum capacity is 1590 lblong dash10 passengers. So, 10 adult male passengers can have a mean weight of up to 1590 divided by 10 equ

Question 1135429: An elevator has a placard stating that the maximum capacity is 1590 lblong dash10 passengers. So, 10 adult male passengers can have a mean weight of up to 1590 divided by 10 equals 159 pounds. If the elevator is loaded with 10 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than 159 lb. (Assume that weights of males are normally distributed with a mean of 168 lb and a standard deviation of 34 lb.) Does this elevator appear to be safe?

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
That probability uses z>=(x bar-mean)/sigma/sqrt(n)
z>=(159-168)/34/sqrt(10)
this is z>=-9*sqrt(10)/34, which is z>=-0.84
This has probability 0.7995
One can't say whether or not it is safe; one may say that with high probability, ten normal men would have a mean weight exceeding the maximum capacity. It would be up to engineers to say with that information whether the elevator itself would be safe.
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SOLUTION: An elevator has a placard stating that the maximum capacity is 1590 lblong dash10 passengers.​ So, 10 adult male passengers can have a mean weight of up to 1590 divided by 10 equ

SOLUTION: An elevator has a placard stating that the maximum capacity is 1590 lblong dash10 passengers. So, 10 adult male passengers can have a mean weight of up to 1590 divided by 10 equ