SOLUTION: A team of four members consisting of eight mathematicians and seven chemists will be selected. Calculate the number of different ways to form a team member if all members are mathe

Question 1134100: A team of four members consisting of eight mathematicians and seven chemists will be selected. Calculate the number of different ways to form a team member if all members are mathematicians? if the number of mathematicians and chemists are equal? if the team contains at least two mathematicians?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
15 total
for four mathematicians only
8/15*7/14*6/13*5/12=0.0513
equal would be 2 of each
total number of ways to choose any four is 15C4=1365
for the numerator 8C2*7C2=28*21=588
the probability is 588/1365=0.4307
At least two mathematicians
for 3 would be 8C3*7C1=56*7=392, and that probability is 0.2872
for 4, 0.0513
So at least two would be the sum of three terms or 0.7692
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