SOLUTION: Here is the question, a quality control manager says that in the manufacturing of DVD players the rate of defects is 3%. Two DVD players are selected at random and checked for defe

Question 1133729: Here is the question, a quality control manager says that in the manufacturing of DVD players the rate of defects is 3%. Two DVD players are selected at random and checked for defects
a.)Find the probability that both DVD players have defects
b.)Find the probability that at least one of the DVD players have defects
c.)The manager selects 10 DVD players at random, what is the probability that all 10 DVD players have defects
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Use the binary probability formula
:
Probability(P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n!/(k! * (n-k)!), p is probability of a success
:
p is given to be 0.03
:
a) P(k = 2 in 2 trials) = 2C2 * (0.03)^2 * (1-0.03)^(2-2) = 0.0009
:
b) P(k = 1 or 2 in 2 trials) = P(k = 1 in 2 trials) +P(k=2 in 2 trials) = 0.0582 +0.0009 = 0.0591
:
c) P(k = 10 in 10 trials) = 10C10 * (0.03)^10 * (1-0.03)^(10-10) = 0
:
Note a success is a failure for this problem
:

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