SOLUTION: A computer company advertises its computers in PC World, in PC Magazine, and on television. A survey of 780 customers finds that the numbers of customers who are familiar with the

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Question 1132870: A computer company advertises its computers in PC World, in PC Magazine, and on television. A survey of 780 customers finds that the numbers of customers who are familiar with the company's computers because of the different forms of advertising are as follows:
305, PC World
280, PC Magazine
310, television
140, PC World and PC Magazine
132, PC Magazine and television
120, PC World and television
83, all three sources
How many of the surveyed customers know about the computers because of:
(a) exactly one of these forms of advertising?

how many customers
(b) exactly two of these forms of advertising?

how many customers
(c) PC World and neither of the other two forms of advertising?
how many customers

Answer by ikleyn(52821)   (Show Source): You can put this solution on YOUR website!
.
We have one "universal" set C of 780 surveyed Customers and many its subsets:


    subset W           (PC World, of 305 customers)

    subset M           (PC Magazine, of 280 customers)

    subset T           (television, of 310 customers)

    subset (WM)        (intersection of the sets W and M, of 140 customers)

    subset (MT)        (intersection of the sets W and M, of 132 customers)

    subset (WT)        (intersection of the sets W and T, of 120 customers)

    subset (WMT)       (intersection of the sets W, M and T, of 83 customers)

(a)   How many of the surveyed customers know about the computers because of exactly one of these forms of advertising?

     How many know from exactly one source W ?

     Take subset W, subtract intersections WM and WT from it, and then add intersection WMT;

     so the number Wo (W only) is equal to  305 - 140 - 120 + 83 = 128.



     How many know from exactly one source M ?

     Take subset M, subtract intersections WM and MT from it, and then add intersection WMT;

     so the number Mo (M only) is equal to  280 - 140 - 132 + 83 = 91.



     How many know from exactly one source T ?

     Take subset T, subtract intersections MT and WT from it, and then add intersection WMT;

     so the number To (T only) is equal to  310 - 132 - 120 + 83 = 141.



     Therefore, the answer to the question  (a)  is the sum

         Wo + Mo + To = 128 + 91 + 141 = 360.     ANSWER to question (a)


(b)   How many of the surveyed customers know about the computers because of exactly two of these forms of advertising?

     To get the number, add elements in WM, MT and WT; then subtract 3 times the number of elements in WMT:

     140 + 132 + 120 - 3*83 = 143.      ANSWER to question (b)


(c)   How many of the surveyed customers know about the computers because of PC World and neither of the other two forms of advertising?

     I just answered this question above, but will repeat it again for your convenience.


     How many know from exactly one source W ?

     Take subset W, subtract intersections WM and WT from it, and then add intersection WMT;

     so the number Wo (W only) is equal to  305 - 140 - 120 + 83 = 128.    ANSWER to question (c)


Everything is answered;  the problem is solved and completed.

-----------------

Regarding similar problems,  see the lessons
    - Counting elements in sub-sets of a given finite set
    - Advanced problems on counting elements in sub-sets of a given finite set
    - Challenging problems on counting elements in subsets of a given finite set
in this site.

Look also into the links

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1129554.html
https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1129554.html
https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.1126097.html
https://www.algebra.com/algebra/homework/word/evaluation/Evaluation_Word_Problems.faq.question.1126099.html

to similar solved problems in the archive of this forum.



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