SOLUTION: A salesperson has a 18% chance of making a sale to any customer called upon. If 6 calls were made what is the probability that exactly 3 sales were made? At most one sale was made?

Question 1132767: A salesperson has a 18% chance of making a sale to any customer called upon. If 6 calls were made what is the probability that exactly 3 sales were made? At most one sale was made? At least two sales were made? What is the mean and standard deviation of the number of sales ?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean is 6*0.18 or 1.08
variance is 6*0.18*0.82 or 0.8856
sd is sqrt (V)=0.9410.
probability of exactly 3 is 6C3*0.18^3*0.82^3=0.0643
probability of 0 is 0.82^6=0.3040
probability of 1 is 6*0.18*0.82^5=0.4004
So probability at most 1 is the sum or 0.7044.
probability of at least 2 sales is 1-probabilty of at most 1 or 0.2956
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