SOLUTION: Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that h

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Question 1131491: Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that he will return home without experiencing a car break-down?



(Please round your answer to four decimal places if necessary. Thank you!)
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

if an old car with a rate of break-downs every that is per days
so that would be per days

parameter is , so probability of is
Answer by ikleyn(52832)   (Show Source): You can put this solution on YOUR website!
.
6 break-downs every four weeks = 6 break-downs every 28 days =  break-downs every 4 days  ====>  


the probability do not have a break-down in 4 days is the COMPLEMENT to  = 1 -  = .      ANSWER

Solved.


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