SOLUTION: If anyone can help me solve this, I would be so appreciative. This is day two of trying to solve this successfully. Thanks.
The amount of​ carbon-14 present in animal bo
Algebra.Com
Question 1130958: If anyone can help me solve this, I would be so appreciative. This is day two of trying to solve this successfully. Thanks.
The amount of carbon-14 present in animal bones after t years is given by P(t)
=P0e superscript−0.00012t. A bone has lost 11% of its carbon-14. How old is the bone?
The bone is ____________years old.
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
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Take natural logs of both sides and solve for t.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The bone has lost 11% of its Carbon-14, so the percent remaining is 89%; the fraction remaining is 0.89. The fraction remaining is the current amount, P(t), divided by the original amount, P(0). So
The given formula for the amount remaining is
That formula is equivalent to
So we want to solve for the number of years t in the equation
Since the exponential is base e, take the natural log of both sides of the equation:
= 971 years to the nearest whole number
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