SOLUTION: assume that a box contains three red jelly beans and two green ones. We consider the event that a red bean is drawn. Suppose I pick a jelly bean from the box without looking, and

Question 1128176: assume that a box contains three red jelly beans and two green ones. We consider the event that a red bean is drawn. Suppose I pick a jelly bean from the box without looking, and I do not put the bean back in the box. Then I choose again. What is the probability of getting two red beans
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
(3/5) probability first is red*(2/4) probability second is red. The second one changes both the numerator and the denominator.
That is 3/10 probability of getting two reds.
Answer by ikleyn(52852) (Show Source): You can put this solution on YOUR website!
.

The probability under the question is

= = = = 0.3 = 30%.

This formula is self-explanatory. If you have questions, look into the formula attentively, and then it will tell you everything about itself.

So, my explanations are not required.

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This problem is the TWIN to the problem which I solved under the link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1128157.html

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1128157.html

Compare them to better learn this subject.

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