SOLUTION: The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.7 days and a standard deviation of 1.5 days.
What is the probability of s
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Question 1127869: The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.7 days and a standard deviation of 1.5 days.
What is the probability of spending more than 4 days in recovery?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Compute the z score with x = 4, mu = 5.7 and sigma = 1.5



which is approximate to 2 decimal places
Use a table such as this one to find that
note: look on page 1 for the row that starts with -1.1, then look at the column that has 0.03 at the top. This row and column intersect with the value 0.1292 inside
So this means,
 = 0.1292)
 = 1-P(Z < -1.13) = 1-0.1292 = 0.8708)
 = 0.8708)
This is approximate to four decimal places
Therefore,
 = 0.8708)
which is also approximate
Final Answer: 0.8708
note: this answer is not entirely perfect due to some rounding errors accumulated. Use a calculator (instead of a table) to get more accurate answer. The reason I'm using a table is that a lot of professors require tables as they are found often in the back of your textbook.
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