SOLUTION: If a committee of 6 is being selected from a group of 10 men and 12 women, in how many ways can this committee be arranged if at least 3 must be women?

Question 1127249: If a committee of 6 is being selected from a group of 10 men and 12 women, in how many ways can this committee be arranged if at least 3 must be women?
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!

C(10,3)*C(12,3) = number of committees with 3 men and 3 women
+C(10,2)*C(12,4) = number of committees with 2 men and 4 women
+C(10,1)*C(12,5) = number of committees with 1 man and 5 women
+C(10,0)*C(12,6) = number of committees with no men and 6 women

= (120)*(220) + (45)*(495) + (10)*(792) + (1)*(924)
= 26400 + 22275 + 7920 + 924
= ways

(assuming I haven't made an error in the calculations)
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