SOLUTION: I am a learning coach trying to help a student.
Please help me try to explain how to do the calculation (do not know the calculation)
A fruit bowl contains 4 apples, 6 bananas,
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Question 1126900: I am a learning coach trying to help a student.
Please help me try to explain how to do the calculation (do not know the calculation)
A fruit bowl contains 4 apples, 6 bananas, 5 pears and 1 orange.
Suppose 2 pieces of fruits are selected from the bowl, and the first piece of fruit selected is replaced before the second piece of fruit is selected. What is the probability 2 pears are selected? What calculation would you use?
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
4 apples, 6 bananas, 5 pears, 1 orange.
total is 16 pieces of fruit.
probability of first piece to be a pear is 5/16.
since the fruit is replaced before picking again, the probability of the second piece being a pear is also 5/16.
the probability of both pieces being selected is 5/16 * 5/16 = 25/256.
here's a reference.
https://www.mathsisfun.com/data/probability-events-conditional.html
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.
You can find many solved elementary probability problems in the lessons
- Elementary Probability problems related to combinations
- A True/False test
- A shipment containing fair and defective alarm clocks
- People in a room write down integer numbers at random
- A drawer contains a mixture of socks
- Students studying foreign languages
- Probability for a computer to be damaged by viruses
- Typical probability problems from the archive
- Geometric probability problems
- Advanced probability problems from the archive
- Challenging probability problems
- Selected probability problems from the archive
- Elementary operations on sets help solving Probability problems
- Unusual probability problems
- Probability problem for the Day of April, 1
- OVERVIEW of lessons on Probability (*)
in this site. You can learn the elementary probability by simply reading these lessons.
The good position to observe all these lessons ("top view") is the last lesson (*) of the list.
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