SOLUTION: Let S = {a, b, c, d, e, f} with P(b) = 0.26, P(c) = 0.14, P(d) = 0.17, P(e) = 0.15, and P(f) = 0.14. Let E = {a, c, f} and F = {b, d, e, f}. Find P(a), P(E), and P(F).
P(a) =
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Question 1125681: Let S = {a, b, c, d, e, f} with P(b) = 0.26, P(c) = 0.14, P(d) = 0.17, P(e) = 0.15, and P(f) = 0.14. Let E = {a, c, f} and F = {b, d, e, f}. Find P(a), P(E), and P(F).
P(a) =
P(E) =
P(F) =
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This can only be solved if you assume \ =\ 1)
, eliminating the possibility of events 
with probabilities greater than zero.
Given such an assumption:
\ =\ 1\ -\ \(P(b)\ +\ P(c)\ +\ P(d)\ +\ P(e)\ +\ P(f)\))
\ =\ P(a)\ +\ P(c)\ +\ P(f))
\ =\ P(b)\ +\ P(d)\ +\ P(e)\ +\ P(f))
You can do your own arithmetic.
John
My calculator said it, I believe it, that settles it
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