SOLUTION: Alexia dug 11 holes labelled one to 11. Each hole is identical in every way. She puts a seed in each hole such that each seed has a probability of 0.6 to germinate.
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Question 1120720: Alexia dug 11 holes labelled one to 11. Each hole is identical in every way. She puts a seed in each hole such that each seed has a probability of 0.6 to germinate.
What is the probability that all seeds will germinate?
What is the probability that only three will not germinate?
What is the probability that more than five will germinate?
What is the expected value that a seed will germinate?
Found 2 solutions by stanbon, Boreal:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Alexia dug 11 holes labelled one to 11. Each hole is identical in every way. She puts a seed in each hole such that each seed has a probability of 0.6 to germinate.
What is the probability that all seeds will germinate?
Ans:: P(x = 11) = 0.6^11 = 0.0036
What is the probability that only three will not germinate?
Ans: P(x = 8) = 11C8*0.6^8*0.4*3 = binompdf(11,0.6,8) = 0.1774
What is the probability that more than five will germinate?
Ans: P(6<=x<=11) = 1 - binomcdf(11,0.6,5) = 0.753
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What is the expected value that a seed will germinate?
E(x) = np = 11*0.6 = 6.6
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Cheers,
Stan H.
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Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
all 11 germinate is 0.6^11 or 0.0036
Only three will not germinate is same as 8 will germinate
That is 11C8*0.6^8*0.4^3=0.1774
More than 5 will germinate is 0-5 won't germinate. That sum is 0.2465 so the answer is 1-0.2465 or 0.7535
Expected value is 11*0.6 or 6.6
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