SOLUTION: Doug throws a ball vertically into the air while standing on a platform that is 10 feet off the ground. The motion of the ball is described by f(t)=-16t^2+96t+10, where t represe

Question 1120640: Doug throws a ball vertically into the air while standing on a platform that is 10 feet off the ground. The motion of the ball is described by
f(t)=-16t^2+96t+10, where t represents seconds and f(t) represents the height (in feet) of the ball above ground level in t seconds. What is the maximum height above ground the ball will reach, and how many seconds will pass before it reaches this height?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Maximum height is where -b/2a for this quadratic equals t, or -96/-32 or 3 seconds for this function.
when t=3, f(t)=-144+288+10=154 feet.

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