SOLUTION: In a sample of 800 U.S. adults, 189 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without re

Question 1120407: In a sample of 800 U.S. adults, 189 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S. adults, complete parts (a) through (d).
A) find the probability that both adults dine out more than once per week
B)find the probability that neither adult dines out more than once per week
C)find the probability that at least one of the two adults done that more than once per week and
D)which of the events can be considered unusual all answers must be rounded to three decimal places as needed
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
a. (189/800)*(188/799)=0.056
b. (611/800)*(610/799)=0.583
c, 1-neither means at least 1, or 0.417
If one considers the 5% level as being unusual, none is.

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SOLUTION: In a sample of 800 U.S.&#8203; adults, 189 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without re

SOLUTION: In a sample of 800 U.S. adults, 189 dine out at a resaurant more than once per week. Two U.S. adults are selected at random from the population of all U.S. adults without re