SOLUTION: Suppose that X is normally distributed with mean 90 and standard deviation 28.
A. What is the probability that X is greater than 141.8?
Probability =
B. What value of X d
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Question 1119878: Suppose that X is normally distributed with mean 90 and standard deviation 28.
A. What is the probability that X is greater than 141.8?
Probability =
B. What value of X does only the top 13% exceed?
X =
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z value is (x-mean)/sd
z=(141.8-90)/28
z>=1.85
probability is 0.0322
top 13% is z=1.126 from the table
1.13=(x-mean)/28
x-mean=31.53
x=121.53 or 121.5
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