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Time interval duration "between 11 minutes and 21 minutes" is 10 minutes:
1 minute from 11 min. to 12 min.
1 minute from 12 min. to 13 min.
1 minute from 13 min. to 14 min.
1 minute from 14 min. to 15 min.
1 minute from 15 min. to 16 min.
1 minute from 16 min. to 17 min.
1 minute from 17 min. to 18 min.
1 minute from 18 min. to 19 min.
1 minute from 19 min. to 20 min.
1 minute from 20 min. to 21 min.
Time interval duration "between 13 minutes and 19 minutes" is 6 minutes:
1 minute from 13 min. to 14 min.
1 minute from 14 min. to 15 min.
1 minute from 15 min. to 16 min.
1 minute from 16 min. to 17 min.
1 minute from 17 min. to 18 min.
1 minute from 18 min. to 19 min.
The probability under the question is the ratio of 6 minutes to 10 minutes = 0.6 = 60%.
Solved.
The solution and the answer by the other tutor are incorrect.
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After reading the @greenestamps solution I added this NOTICE.
The meaning of this problem is THIS:
I have a stop watch. I turn it on when I start dish washing, and I stop it when the process ends.
I write the reading of the stop watch after every/each experiment.
Then I see that the readings for the process duration are uniformly distributed over the time interval between 11 minutes
(=from the start of the 11-th minute reading) and 21 minutes (=to the complete end of the 20-th minute,
i.e. to the moment, when 21-th minute starts).
. . . And so on to the end of the condition.
This problem HAS THIS and ONLY THIS reading and meaning.
Nothing else. // The words "uniformly distributed" of the condition do not leave the place (the gap) for any other interpretation.
Any different interpretation is FALSE and IRRELEVANT.
In particular, the proposed by @greenestamps interpretation is wrong.
I agree that the problem formulation is not perfect, since it does not determine if 21-th minute is included completely or not.
If it is included (as well as the 19-th minutes is fully included), then the answer is .
But in any case two continuous time intervals are considered, and there is no place for a "discrete" interpretation.
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It is a STANDARD introductory problem on geometric probability.
To see other similar solved problems, look into the lesson
- Geometric probability problems
in this site.