SOLUTION: In a binomial distribution n = 7 and p = 0.25. Find the probabilities of the following events: (Round the final answers to 3 decimal places.)
a. x = 2.
Probability :
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Question 1118174: In a binomial distribution n = 7 and p = 0.25. Find the probabilities of the following events: (Round the final answers to 3 decimal places.)
a. x = 2.
Probability :
b. x ≤ 2 (the probability that x is equal to or less than 2).
Probability :
c. x ≥ 3 (the probability that x is equal to or greater than 3).
Probability :
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
for x=2
7C2*(0.25)^2*0.75)^5=0.311
x<=2, need 1 and 0
7*0.25*0.75^6=0.337
1*.75^7=0.133
That sum is 0.782, if I use the 4 decimal place answers and then roun.
probability x>=3 is 1- the above, since this is a discrete, dichotomous function, and that is 0.218.
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