SOLUTION: 3000 packs of tea were weighed and found to be normally distributed with mean of 225 grams and standard deviation of 2.5 grams. What percent of the data lies between 220 grams and

Question 1117147: 3000 packs of tea were weighed and found to be normally distributed with mean of 225 grams and standard deviation of 2.5 grams. What percent of the data lies between 220 grams and 230 grams?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3000 packs of tea were weighed and found to be normally distributed with mean of 225 grams and standard deviation of 2.5 grams. What percent of the data lies between 220 grams and 230 grams?
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Note:: The standard deviation of the sample means is 2.5/sqrt(3000)
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Find the z-value of 220 and 230.
Then find the percentage between those z-values.
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Cheers,
Stan H.
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