SOLUTION: Urn 1 has 2 white and 3 black balls : Urn 2 has 4 white and 1 black:Uen 3 has 3 white and 4 black. An Urn is selected to be white.find the probability that Urn 1 was selected.

Algebra.Com
Question 1117092: Urn 1 has 2 white and 3 black balls : Urn 2 has 4 white and 1 black:Uen 3 has 3 white and 4 black. An Urn is selected to be white.find the probability that Urn 1 was selected.
Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
The condition was written so inaccurately  that clearly showed that the person who wrote it  did not understand the meaning of what he wrote.

The correct formulation is   T H I S:

    Urn 1 has 2 white and 3 black balls; Urn 2 has 4 white and 1 black; Urn 3 has 3 white and 4 black. 
    A ball was selected to be white. Find the probability that the ball was selected from Urn 1.


Solution

In all,  there are   2 + 4 + 3 = 9  white balls.


Therefore,  the answer/(the probability under the question) is  .

Solved.


RELATED QUESTIONS

There are 3 urns containing 2 white and 3 black balls, 3 white and 2 black balls and 4... (answered by richwmiller)
An urn B1 contains 2 white and 3 black balls and another urn B2 contains 3 white and 4... (answered by greenestamps)
Please help me on this question. Two urns contain white and black balls. Urn 1... (answered by robertb)
An urn contains 5 white and 7 black balls. Another urn contains 3 white and 9 black... (answered by greenestamps)
the constitution of 2 urns: first urn has 3 black balls and 2 whites second urn has 4... (answered by robertb)
Urn 1 contains 6 red balls and 5 black balls. Urn 2 contains 3 red balls and 3 black... (answered by Boreal)
Please help me on this question. Thanks! Two urns contain white and black balls. Urn 1... (answered by robertb)
One of two urns is chosen at random with one as likely to be chosen as the other. Then a... (answered by ewatrrr)
Urn 1 contains 3 red balls and 4 black balls. Urn 2 contains 4 red balls and 2 black... (answered by jim_thompson5910)