.
The percentage read at least one of the newspapers = (0.2 + 0.16 + 0.14 - 0.08 - 0.05 - 0.04 + 0.02)*100 = 35%.
The first approximation is to add 20%, 16% and 14%. (1)
But in this way we count elements/(readers) in each intersection AB, AC and AB twice.
Therefore, we subtract 8%, 5% and 4%. (2)
But in this way, we loose everything/(everybody) in the intersection ABC (because we counted it/(them) thrice first in the step (1),
and then excluded it/(them) thrice in the step (2). )
Therefore, we add 2% as the last correction step.
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See the lessons
- Counting elements in sub-sets of a given finite set
- Advanced problems on counting elements in sub-sets of a given finite set
in this site.