SOLUTION: A box contains 44 ​red, 33 white and 44 green balls. Two balls are drawn out of the box in succession without replacement. What is the probability that both balls are the sam
1. 44 + 33 + 44 = 121.
2. The probability to get two red balls = .
The probability to get two white balls = .
The probability to get two green balls = .
3. The probability to get two balls of the same color is
= = = = = = 0.3333 = 33.33%.