SOLUTION: A bag contain 8 red 6 blue balls.two drawing of each 2 ballasts made find the probability that the first drawing two red balls and second drawing 2 blue balls, if the balls drawn f
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Question 1113307: A bag contain 8 red 6 blue balls.two drawing of each 2 ballasts made find the probability that the first drawing two red balls and second drawing 2 blue balls, if the balls drawn first are replaced before the second draw
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
there are 14 balls in the bag
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Probability of drawing two red balls = (8/14) * (7/13) = 4/13
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Probability of drawing two blue balls = (6/14) * (5/13) = 15/91
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Probability of drawing 2 red balls and 2 blue balls = (4/13) * (15/91) = 60/1183
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Note I assume a single ball drawn is not replaced until after the second ball is drawn
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