SOLUTION: in 1959, a world record was set for the longest run on an ungaffed (fair) roulette wheel at the el san juan hotel in puerto rico. the number 10 appeared six times in a row. what is
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Question 1113205: in 1959, a world record was set for the longest run on an ungaffed (fair) roulette wheel at the el san juan hotel in puerto rico. the number 10 appeared six times in a row. what is the probability of the occurrence of this event? (assume that there are 38 equally likely outcomes consisting of the numbers 1-36, 0, and 00))
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The probability of 
successes in 
trials with a probability of success on any single trial is 
is given by:
\ =\ {{n}\choose{k}}\ \(p\)^k\,\cdot\,\(1\ -\ p\)^{n\,-\,k})
You want to calculate
\ =\ {{6}\choose{6}}\ \(\frac{1}{38}\)^6\,\cdot\,\(\frac{37}{38\)^{0})
Note that 
for all positive integers 
and 
for all real numbers 
. Hence your calculation reduces to:
\ =\ \(\frac{1}{38}\)^6)
Break out your calculator...
John
My calculator said it, I believe it, that settles it
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